**1. SCOPE**

The purpose of this educational module is to present the response spectrum method of earthquake response analysis/design of mechanical and electrical equipment and supports. Equipment and supports are modeled as a single-degree-of-freedom (SDOF) system. No prior knowledge of structural vibration analysis or earthquake analysis is required to understand this module.

**2. INTRODUCTION**

Four methods of earthquake response analysis of equipment are available.

1. Simplified procedures such as those provided in ASCE 7-05 Standard [1]

2. SDOF response spectrum method

3. MDOF response spectrum method

4. Time-history method

**- Single-degree-of-freedom**

*SDOF**- Multiple-degrees-of-freedom*

**MDOF**The SDOF response spectrum method, presented in this educational module, can be used as long as the equipment and supports can be modeled by a single-degree-of-freedom system consisting of a spring, mass and damping. The SDOF response spectrum method usually gives less conservative results than simplified procedures, yet is easy to perform. It is far easier to perform than MDOF response spectrum analysis or time-history analysis that require special computer software.

**3. SDOF MODEL**

The equipment and supports are modeled as a SDOF system as represented in Figure 1.

Figure 1: Single-Degree-of-Freedom System Model |

c = damping,

k = stiffness,

m = mass, and

x = displacement of the mass

k = stiffness of supports in the direction of the earthquake motion (If a horizontal earthquake motion is considered, then k is the corresponding horizontal stiffness of the supports; if vertical earthquake motion is considered, then k is the vertical stiffness of the supports.)

k = stiffness,

m = mass, and

x = displacement of the mass

k = stiffness of supports in the direction of the earthquake motion (If a horizontal earthquake motion is considered, then k is the corresponding horizontal stiffness of the supports; if vertical earthquake motion is considered, then k is the vertical stiffness of the supports.)

m = w/g

**(1)**

where w = weight of SDOF = weight of equipment + half the weight of supports

g = acceleration due to gravity

Damping is often specified as a percentage of critical damping, or simply damping percentage, and denoted by ξ. As an example, 2% damping is often used for welded steel construction in some industries. Damping may also be presented as damping ratio, again denoted by ξ. If percentage of critical damping is 2%, then damping ratio is 0.02.

**4. NATURAL FREQUENCY AND PERIOD OF THE SDOF SYSTEM**

Natural frequency of the SDOF system in radians per second is given by

ω

Natural frequency in cycles per second is given by

f = ω/2π

Cycles/second is also known as hertz.

Period of the SDOF system in seconds is given by

T = 1/f

^{2}= k/m**(2)**Natural frequency in cycles per second is given by

f = ω/2π

**(3)**Cycles/second is also known as hertz.

Period of the SDOF system in seconds is given by

T = 1/f

**(4)****5. RESPONSE SPECTRUM**

A family of acceleration response spectra for various damping values is shown in Figure 2. Horizontal axis is the frequency in hertz (hz) and vertical axis is the maximum acceleration of the mass as a multiple of g. This family of response spectra represents a given base motion of the SDOF system. (Note: Sometimes acceleration response spectra are plotted as "Period versus maximum acceleration" instead of "frequency versus maximum acceleration". Velocity response spectra and displacement response spectra are also sometimes used. In those cases the vertical axis is maximum velocity or maximum displacement, as appropriate.)

If the equipment is located at the ground level, then the ground acceleration spectra are used in the analysis. There will be separate families of horizontal and vertical spectra corresponding to the horizontal and vertical earthquake motions.

If the equipment is located at a higher floor of a building, then the response spectra for the earthquake motion at that floor are used in the analysis. Such spectra are called "in structure response spectra" or "floor response spectra". Such spectra are usually provided by the architect-engineer or seismic structural analyst of the building.

**6. RESPONSE COMPUTATION**

**6.1 Maximum Acceleration**

The maximum acceleration experienced by the mass (in the direction of the earthquake motion) is read from the acceleration response spectra curves. The procedure will be illustrated in the solved example problem.

**6.2 Maximum Velocity and Displacement**

Maximum velocity and displacement may be determined from the velocity and displacement response spectra, if available. Alternately, maximum velocity and displacement may be computed from the maximum acceleration using the following approximate equations.

Maximum relative velocity = Maximum acceleration/ω

**(5)**

Maximum relative displacement = Maximum velocity/ω

**(6)**

Maximum acceleration in eqn. 5 should be specified in inch/sec

^{2}or feet/sec

^{2}(not as a multiple of g).

The above velocity and displacement are relative to the base.

6.3 Maximum Force

6.3 Maximum Force

Maximum force on the mass may be computed by multiplying mass by the maximum acceleration. Maximum acceleration should be specified in inch/sec

^{2}or feet/sec

^{2}.

Maximum force = mass x maximum acceleration (7)

**7. Load combination**

If the design code or design guide requires that responses from more than one direction of the earthquake motion need to be combined, then each individual response is computed separately as described above and then the responses are combined per design code/guide.

**8.NUMERICAL EXAMPLE**

**Problem:**

Equipment weighs 4000 pounds. Support weight is 80 pounds. Support stiffness in the direction of earthquake motion is 50000 pounds/inch. Damping is 5%. The earthquake motion is represented by the response spectra shown in Figure 2. Compute the maximum acceleration, velocity, displacement and force in the direction of the earthquake motion.

**Solution:**

System weight w = weight of equipment + half the weight of supports = 4000 + 0.5 (80) = 4040 lb

g = 386.4 inch/sec2

System mass m = 4040/386.4 = 10.45 lb-sec2/inch

Stiffness = 50000 lb/inch

Using eqn. 2,

ω

Natural frequency ω = 69.2 radians/second

ω

^{2}= k/m = 50000 / 10.45 = 4784Natural frequency ω = 69.2 radians/second

Per eqn. 3, natural frequency in cycles/sec (hertz) is

f = ω/2π = 69.2/2π = 11 hertz

Per eqn. 4, period is

T = 1/f = 1/11 = 0.09 sec

Percentage of critical damping = 5%

Maximum acceleration is obtained from Figure 2. Go to 11 hertz on the horizontal axis.

Draw a vertical line and go up to the 5% response spectra. The maximum acceleration thus read is approximately equal to 0.6g.

Maximum acceleration = 0.6g = 0.6 x 386.4 = 231.8 inch/sec

^{2}

Using eqns. 5, 6 and 7,

Maximum relative velocity = 231.8/69.2 = 3.35 inch/sec

Maximum relative displacement = 3.35/69.2 = 0.05 inch

Maximum force = 10.45 x 231.8 = 2422 lb

9. REFERENCE

9. REFERENCE

1. "Minimum Design Loads for Buildings and Other Structures", ASCE/SEI 7-05, American Society of Civil Engineers, 2005.

## 0 comments:

## Post a Comment

Share your views or discuss.